NPCIL Recruitment 2018 – 179 Vacancies for Stipendiary Trainee
NPCIL Recruitment 2018 – 179 Vacancies for Stipendiary Trainee
| Nuclear Power Corporation of India Limited (NPCIL) has released a notification for the recruitment of 179 Stipendiary Trainees as Technician-‘B’ and Scientific Assistant/B. Interested candidates may check the vacancy details and apply before 21-05-2018. More details about NPCIL Recruitment (2018), including number of vacancies, eligibility criteria, selection procedure, how to apply and important dates, are given below: |
| Vacancy Details: •Post Name: Stipendiary Trainee (Technician-‘B’) •No. of Vacancies: 117 •Pay Scale: Rs. 10,500 |
•Post Name: Stipendiary Trainee (Scientific Assistant/B)
•No. of Vacancies: 62
•Pay Scale: Rs. 16,000Job Location: Tamil NaduEligibility Criteria for NPCIL Stipendiary Trainee:Educational Qualification:
For Technician-‘B’: Candidates should have passed 10th/10+2 with 50% marks in relevant subjects from a recognised board.
For Scientific Assistant/B: Candidates should have passed B.Sc. OR Diploma with 60% marks from a recognised board.Age Limit (as on 21-05-2018):
For Technician-‘B’: Minimum 18 years and Maximum 24 years
For Scientific Assistant/B: Minimum 18 years and Maximum 25 yearsSelection Process: Selection of candidates will be made on the basis of Written Test and Skill Test.Application Fee: No Application FeeHow to Apply: Interested and eligible candidates may apply by sending their application form along with photocopies of relevant documents and passport size photographs to Manager (HRM), HR Section, Kudankulam Nuclear Power Project, Kudankulam PO, Radhapuram Taluk, Tirunelveli District, Tamil Nadu-627106 before 21-05-2018.
Important Dates:
• Last Date of Application: 21-05-2018
Important Links:
Detail Advertisement Link & Application Form
Official Website
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I am not able to apply for stipendry trainee post. page not found is written when I click on application form.